Constant Voltage Source
For the first case lets look at constant voltage. The power dissipated in the load is P = V2/R. Here R is the load resistance and V is the applied voltage. However, R is a function of temperature, T, given by R = Ro*(1 + a*(T-To) ) where the resistance is linear with temperature and has a value Ro at temperature To. The steady-state temperature is also a function of the temperature given by the dissipation characteristics of the thermal system T = Tamb + theta*P where theta is the thermal resistance (C/W) and Tamb is the ambient temperature. Intuitively you can see that when the voltage is applied the power increases the temperature which in turn increases the resistance (assuming a positive temperature coefficient, a). The increase in resistance then reduces the power. This is inherent negative feedback at play that prevents a runaway thermal condition.
Combining these three equations we can solve for the temperature as
(dT)2 + (1/a)*(dT) - V2*Theta/(a*R0) = 0
Where dT = (T-Tamb). This is a non-linear system. The block diagram is shown below as a feedback network. I also added a thermal time constant to the thermal resistance block. The loop gain is found using small signal gain theory to be -(a*Ro*Theta*I2(dT)) which is negative for a>0.

Constant Current Source
The second case we will look at is a constant current supply. In this case the power dissipation is given by P = I2 * R. We can see intuitively that power dissipation raises the temperature which raises the resistance and therefore increases the power dissipation. This is a case of positive feedback and hence has the potential for thermal runaway. Solving the three equations for power, resistance and temperature we have the result for temperature rise
(T-Tamb) = (I2*R0*Theta) / (1 - (a*Theta*I2*R0))
This is a linear system and has the form of a closed loop equation with open loop gain a*Ro*Theta*I2. In the block diagram below I added a thermal time constant to the thermal resistance block.

Note that for positive temperature coeffficents (a>0) this system has positive feedback. If the loop gain gets too close to unity there will be a thermal runaway condition. Some boundary conditions are: 1. If the temperature coefficient is negative (a<0) dt=I2*R0*Theta, 2. Perfect Heat sink (Theta=0) then dT= 0 and 3. Perfect Short R=0 then dT= 0. The loop gain can be used as a measure of the safety factor in a system design.
This basic analysis of the feedback mechanism in a self heating system has many applications. Who would of thought that a handful of variables would say so much about a system?
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